Category: Other : Precalculus

Given the cost function C(x)=0.85x+35,000?(?)=0.85?+35,000 and the revenue function R(x)=1.55x,?(?)=1.55?, the break-even point is (50,000,77,500) and the profit function is P(x)=0.7x−35,000. Solution Write the system of equations using y? to replace function notation. y=0.85x+35,000y=1.55x?=0.85?+35,000?=1.55? Substitute the expression 0.85x+35,0000.85?+35,000 from the first equation into the second equation and solve for x.?. 0.85x+35,000=1.55×35,000=0.7×50,000=x0.85?+35,000=1.55?35,000=0.7?50,000=? Then, we substitute x=50,000?=50,000 into either the cost function or the revenue function. 1.55(50,000)=77,5001.55(50,000)=77,500 The break-even…

Given the cost function C(x)=0.85x+35,000?(?)=0.85?+35,000 and the revenue function R(x)=1.55x,?(?)=1.55?, the break-even point is (50,000,77,500) and the profit function is P(x)=0.7x−35,000. Solution Write the system of equations using y? to replace function notation. y=0.85x+35,000y=1.55x?=0.85?+35,000?=1.55? Substitute the expression 0.85x+35,0000.85?+35,000 from the first equation into the second equation and solve for x.?. 0.85x+35,000=1.55×35,000=0.7×50,000=x0.85?+35,000=1.55?35,000=0.7?50,000=? Then, we substitute x=50,000?=50,000 into either the cost function or the revenue function. 1.55(50,000)=77,5001.55(50,000)=77,500 The break-even…